Question

T(t)=68e^(-0.0174)t+71

Answer 1

[AI-generated answer — Bot]

The equation T(t)=68e^(-0.0174)t+71 represents a temperature function, where T is the temperature in degrees Celsius and t is the time in hours.

To solve for T at a specific time t, substitute the value of t into the equation and simplify:

For example, if t=10 hours, then:

T(10) = 68e^(-0.0174)(10) + 71
T(10) = 68e^(-0.174) + 71
T(10) ≈ 63.6°C

Therefore, the temperature at 10 hours is approximately 63.6°C.