T(t)=68e^(-0.0174)t+71
What is the temperature of the object after 1.5 hours?
To find the temperature of the object after 1.5 hours, we need to substitute t=1.5 in the given equation:
T(1.5) = 68e^(-0.0174*1.5) + 71
T(1.5) = 68e^(-0.0261) + 71
Using a calculator, we can evaluate e^(-0.0261) as 0.974, and then multiply it by 68:
T(1.5) = 68 * 0.974 + 71
T(1.5) = 66.232 + 71
T(1.5) = 137.232
Therefore, the temperature of the object after 1.5 hours is approximately 137.232 degrees.
To find the temperature of the object after 1.5 hours, we need to substitute the value of t as 1.5 in the given equation:
T(t) = 68e^(-0.0174t) + 71
Substituting t = 1.5 in the equation:
T(1.5) = 68e^(-0.0174 * 1.5) + 71
Now, we can calculate the temperature by evaluating the expression:
T(1.5) ≈ 68e^(-0.0261) + 71
To evaluate e^(-0.0261), we need to use the exponential function on a scientific calculator or a math software. The value of e^(-0.0261) is approximately 0.9746.
Now, substituting this value in the equation:
T(1.5) ≈ 68 * 0.9746 + 71
T(1.5) ≈ 66.22 + 71
T(1.5) ≈ 137.22
Therefore, the temperature of the object after 1.5 hours is approximately 137.22 degrees.
To find the temperature of the object after 1.5 hours, you can substitute the value of t = 1.5 into the equation T(t) = 68e^(-0.0174t) + 71.
T(1.5) = 68e^(-0.0174 * 1.5) + 71
First, calculate the exponential term inside the parentheses:
e^(-0.0174 * 1.5) ≈ 0.9853
Now substitute this value back into the equation:
T(1.5) = 68 * 0.9853 + 71
Multiply 68 by 0.9853:
T(1.5) ≈ 66.8884 + 71
Now add 71 to 66.8884 to get the final result:
T(1.5) ≈ 137.888