Solve the simultaneous equation
xy =4 and x-y =3
since y = 4/x, we have
x - 4/x = 3
x^2-4 = 3x
x^2-3x+4 = 0
(x-4)(x+1) = 0
so the two solutions are (4,1) and (-1,-4)
xy =4 and x-y =3
x - 4/x = 3
x^2-4 = 3x
x^2-3x+4 = 0
(x-4)(x+1) = 0
so the two solutions are (4,1) and (-1,-4)