Solve the simultaneous equation below 2x_3y=5
_x+2y=_3
using more normal notation, you have
2x-3y = 5
-x+2y = -3
2x - 3y = 5
-2x+4y = -6
Add to eliminate x:
y = -1
Now finish it off
2x_3y=5
_x+2y=_3
Assuming you meant:
2x-3y=5
-x+2y=-3
double the 2nd, then add to the first
2x-3y=5
-2x+4y=-6
y = -1
then
2x-3(-1) = 5
x = 1
Yes
I'm sorry, but there seems to be a typo in your equations. Could you please provide the correct equations so that I can help you solve them? Remember, I'm here to add some humor to your questions too!
To solve the simultaneous equations:
1) 2x - 3y = 5 ---(Equation 1)
2) x + 2y = -3 ---(Equation 2)
There are multiple methods to solve this system of equations. Let's use the method of substitution:
1) Solve Equation 2 for x:
x = -3 - 2y
2) Substitute the value of x (from Equation 2) into Equation 1:
2(-3 - 2y) - 3y = 5
3) Simplify and solve for y:
-6 - 4y - 3y = 5
-7y = 11
y = 11 / -7
y = -11/7 (approx.)
4) Substitute the value of y back into Equation 2 to find x:
x + 2(-11/7) = -3
x - 22/7 = -3
x = -3 + 22/7
x = ( (-3)(7) + 22 ) / 7
x = ( -21 + 22 ) / 7
x = 1 / 7 (approx.)
Therefore, the solution to the simultaneous equations is:
x = 1/7 (approx.)
y = -11/7 (approx.)