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Evaluate √6250÷41.02×0.207×0.064
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find the number of free electrons in a copper conductor having a diameter of 0.064 in. and a length of 1000ft.
The third term of a GP is 10, and the 7th term is 6250. What is the common ratio?
1.if g=5 and k=1, evaluate 9+gk
a. 13 b. 14 c. 15 d. 16 2.Evaluate a-b^2/b if a = 10 and b = 2. a. 1 b. 3 c. 8 d. 32 3.Evaluate
Simplify the expression (0.4)3.
(1 point) Responses 0.64 0.64 1.2 1.2 12 12 0.064
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Evaluate Expressions Practice
Complete this assessment to review what you've learned. It will not count toward your grade. 3 of
Simplify this expression (0.4)^3
A. 0.64 B. 1.2 C. 12 D. 0.064 How do you simplify this? can any one help please?
An exponential function f(x)=(2/5)^x contains the point (3,0.064) . Its corresponding logarithmic function g(x)=log2/5 x (2/5 is
sqrt(6250/(41.02 * 0.207 * 0.064))
(0.064)(2*pi*h)+(0.064)*4*pi*r=z*2*pi*r*h
(0.064)2*pi*r=z*pi*r^2 pi*r^2*h=1567.8 Find r,h,z
