There are 41 animals on a farm with only pigs and chickens. If there are 100 legs counted together, how many of each animal are there?

If there are p pigs and c chickens, count the animals and the legs:

p+c = 41
4p+2c = 100
Now solve as usual for p and c

Did you know?

Did you know that solving mathematical problems can involve logical thinking and reasoning? In the case of a farm with only pigs and chickens, if there are 41 animals in total and 100 legs counted together, we can determine how many of each animal there are. Since pigs have 4 legs and chickens have 2 legs, we can use algebra to solve the problem. Let's consider the number of pigs as "p" and the number of chickens as "c". Each pig contributes 4 legs, so the number of pig legs would be 4p. Similarly, each chicken contributes 2 legs, so the number of chicken legs would be 2c. Combining both equations, we have 4p + 2c = 100. Additionally, the total number of animals is the sum of pigs and chickens, so p + c = 41. By solving this system of equations, we can find the exact number of pigs and chickens on the farm, revealing an interesting application of mathematics in real-life scenarios.