The isotope nobelium-259 has a half-life of 58min. How much of the isotopes will remain of a 2 kg sample after 1 day?
a = 2 e^- k t
1 = 2 e*-58 k
ln . 5 = -58 k
k = 0.01195
when t = 24 * 60 = 1440 min
a = 2 e^-0.01195*1440 = 2 e^- 17.2
= 0.000000067
not much
with m measured in grams, and t in minutes, we have
m(t) = 2000 (1/2)^(t/58)
so since a day is 1440 minutes,
m(1440) = 2000 (1/2)^(1440/58) = 0.00006717