The hydroxide of metal y reacts with hydrochloric acid as follow
Y(OH)2+2HCL product YCl2+2H20
It was found that 5.8g of Y(0H)2 reacted with 0.2M hydrochloric acid .calculate the a) molar mass of Y(0H)2
B)atomic mass of y
Help is needed step by step
Please anyone help me collect way to answer step by step
Molarity of HCL= 0.2M
Number of Mole = Molarity x Volume of solution
= 0.2 x 1dm³
=0.2M
Number of mole = 0.2 ÷2 = 0.1mole
Molarmass = Mass/Number of Mole
= 58g/mol.
Y(OH)2 =58g/mol
Y + 34= 58 g/mol
Y= 24.
A) To calculate the molar mass of Y(OH)2, we need to use the given information.
We know that 5.8g of Y(OH)2 reacted with 0.2M hydrochloric acid.
First, let's calculate the number of moles of Y(OH)2:
Moles of Y(OH)2 = mass / molar mass
Moles of Y(OH)2 = 5.8g / molar mass
We also know that the reaction is a 1:1 ratio, meaning each mole of Y(OH)2 reacts with one mole of hydrochloric acid. Therefore, the number of moles of Y(OH)2 is equal to the number of moles of hydrochloric acid used in the reaction.
Number of moles of Y(OH)2 = number of moles of HCl = 0.2 mol/L * volume of HCl used (in liters)
Since the volume of HCl used is not given, we can't directly calculate the moles of Y(OH)2. However, we can rearrange the equation to solve for the molar mass of Y(OH)2.
Molar mass = mass / moles of Y(OH)2
Molar mass = 5.8g / (0.2 mol/L * volume of HCl used)
B) The atomic mass of Y can be determined from the molar mass of Y(OH)2.
Since Y(OH)2 has one atom of Y, the molar mass of Y(OH)2 is equal to the atomic mass of Y.
So the atomic mass of Y is the same as the molar mass of Y(OH)2.
Keep in mind that without knowing the volume of hydrochloric acid used, we can't calculate the molar mass of Y(OH)2 or the atomic mass of Y.
To solve this problem, we need to use the concept of stoichiometry. Stoichiometry is a branch of chemistry that deals with the quantitative relationships between reactants and products in a chemical reaction.
We are given the balanced chemical equation:
Y(OH)2 + 2HCl → YCl2 + 2H2O
a) To calculate the molar mass of Y(OH)2, we need to know the number of moles of Y(OH)2 and the mass of Y(OH)2.
Given:
Mass of Y(OH)2 = 5.8g
Concentration of HCl = 0.2M
First, we need to determine the number of moles of Y(OH)2. We can use the formula:
Moles = Mass / Molar mass
Since we have the mass of Y(OH)2, we can rearrange the formula to find the molar mass:
Molar mass = Mass / Moles
To find the number of moles of Y(OH)2, we can use the concentration and the stoichiometry of the reaction. In this case, we know that one mole of Y(OH)2 reacts with two moles of HCl.
Number of moles of Y(OH)2 = 0.2M (concentration of HCl) × Volume of HCl (to be calculated) × 2 (stoichiometry of Y(OH)2 to HCl)
To find the volume of HCl, we rearrange the concentration formula:
Concentration = Moles / Volume
Volume = Moles / Concentration
Substituting the given values, we can calculate the volume of HCl.
Once we have the volume of HCl and the number of moles of Y(OH)2, we can find the molar mass of Y(OH)2 by dividing the mass by the moles.
b) To calculate the atomic mass of Y, we need to know the molar mass of Y(OH)2, which we calculated in part a. From the balanced equation, we can see that one mole of Y(OH)2 contains one mole of Y.
Atomic mass of Y = Molar mass of Y(OH)2
Using these calculations, we can find both the molar mass of Y(OH)2 and the atomic mass of Y.
a.
Y(OH)2 + 2HCl ==> YCl2 + 2H20
mols HCl = M x L = ?
You don't have enough information. You didn't give the amout of 0.2 M HCl used in the reaction.