What is the molarity of the lithium hydroxide solution if 34.6mL reacts with 17.5 mL of .693 M hydrochloric acid?
To find the molarity of the lithium hydroxide solution, we can use the concept of stoichiometry and the balanced chemical equation.
The balanced chemical equation for the reaction between lithium hydroxide (LiOH) and hydrochloric acid (HCl) is:
LiOH + HCl → LiCl + H2O
From the equation, we can see that the ratio of LiOH to HCl is 1:1.
Given that 34.6 mL of LiOH solution reacts with 17.5 mL of 0.693 M HCl, we can use the following formula:
Molarity (M1) × Volume (V1) = Molarity (M2) × Volume (V2)
M1 and V1 are the molarity and volume of the hydrochloric acid solution, respectively.
M2 and V2 are the molarity and volume of the lithium hydroxide solution, respectively.
Plugging in the values we have:
0.693 M × 17.5 mL = M2 × 34.6 mL
Simplifying the equation:
(0.693)*(17.5) = M2*(34.6)
12.1025 = 34.6*M2
Now we can solve for M2 by dividing both sides of the equation by 34.6:
M2 = 12.1025 / 34.6
M2 ≈ 0.35 M
Therefore, the molarity of the lithium hydroxide solution is approximately 0.35 M.
To find the molarity of the lithium hydroxide (LiOH) solution, we can use stoichiometry and the balanced chemical equation for the reaction between lithium hydroxide and hydrochloric acid.
First, let's write the balanced equation for the reaction:
LiOH + HCl -> LiCl + H2O
From the balanced equation, we know that 1 mole of LiOH reacts with 1 mole of HCl.
Given:
Volume of HCl solution (VHCl) = 17.5 mL
Molarity of HCl solution (MHCl) = 0.693 M
We need to find the molarity of the LiOH solution (MLiOH).
To solve this, we can use the equation:
MLiOH * VLiOH = MHCl * VHCl
Where:
MLiOH = molarity of LiOH solution
VLiOH = volume of LiOH solution
MHCl = molarity of HCl solution
VHCl = volume of HCl solution
Substituting the values we have:
MLiOH * VLiOH = 0.693 M * 17.5 mL
Now, let's solve for the volume of LiOH solution (VLiOH):
VLiOH = (0.693 M * 17.5 mL) / MLiOH
We are given the volume of HCl solution (VHCl) as 34.6 mL, so let's substitute that value:
VLiOH = (0.693 M * 17.5 mL) / 34.6 mL
Now, we can solve for MLiOH by rearranging the equation:
MLiOH = (0.693 M * 17.5 mL) / (34.6 mL)
By plugging the values into a calculator, we can find the answer:
MLiOH = 0.352 M
Therefore, the molarity of the lithium hydroxide solution is 0.352 M.
LiOH + HCl ==> LiCl + H2O
mols HCl = M x L = ?
Since 1 mol LiOH = 1 mol HCl, then mols LiOH will be the same as moles HCl .
The M LiOH = mols LiOH/L LiOH = ? M