can some one help me with this question
The inner surface of a bowl is of the shape formed by rotating completely about the y- axis the
area bounded by the curve π¦ = π₯^2 β 4 , the x β axis, the y β axis and the line π¦ = 3 .
(i) Find the volume of the bowl
(ii) Find the formula that represents the volume of water in the bowl when the depth of water is d (< 3)
If water is poured in at a rate of 5 cubic units per second
(iii) Find the rate at which the depth is increasing when π = 1.
(i) using discs of thickness dy,
v = β«[0,3] Οr^2 dy
where r = x = β(y+4)
v = β«[0,3] Ο(y+4) dy = 33Ο/2
(ii) v = β«[0,d] Ο(y+4) dy = Ο(d^2/2 + 4d)
(iii) dv/dt = Ο(d+4) dd/dt
so plug in your numbers
check on (i) using shells of thickness dx
v1 = 12Ο
v2 = β«[2,β7] 2Οx(3-(x^2-4) dx = 9Ο/2
v = 12Ο + 9Ο/2 = 33Ο/2