Construct a quadrilateral PQRS sue that PQ = 8cm , QPS = 105 ° , measure of angle PQS = 30° ,PR = 9cm RS = RQ
I need the answer
I assume you can construct a right angle, a 60° angle, and can bisect an angle. If not, see online for examples.
draw PQ of length 8
construct QPS (90° + 60°/4)
construct PQS (60°/2) and extend the ray QS as needed to where it meets ray PS at S.
with P as center, draw an arc of radius 9, to where it will intersect QS
R will lie on the perpendicular bisector of QS, where it intersects the arc.
Please do this.
To construct a quadrilateral PQRS, follow these steps:
1. Start by drawing a line segment PQ of length 8 cm.
2. At point P, construct an angle QPS of 105° using a protractor. This will give you point S on one side of the angle.
3. Using a protractor, construct an angle PQS of 30° at point P. This will give you point R on the other side of the angle.
4. Measure 9 cm from point P along the line segment PR and mark this point as point R.
5. Finally, draw a line segment RS of length equal to the line segment RQ, connecting points R and S.
By following these steps, you will construct quadrilateral PQRS with the given conditions.