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Town Y and Town Z were 512 km apart. Car A left Town Y for Town Z at a speed of 32km/h. An hour later car B left Town Z for Town Y at twice of car A ‘s speed. How long would it take for the two cars to pass each other after car b left town Z?

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Xander

  1. distance = speed * time
    So, if B traveled for time t hours, then
    32(t+1) + (2*32)t = 512
    Now just solve for t.

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    oobleck

  2. when b leaves the distance between cars is d = 512 - 1 Sa
    speed = Sa + Sb = Sa + 2Sa = 3 Sa
    so
    3 Sa t = 512 - 1 Sa
    3 * 32 * t = 512-32 = 480
    t = 480/96 = 5 hr

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    Anonymous

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