Use point-slope form to write the equation of a line that has a slope of 2/3 and passes through (-3, -1). Write the equation in slope-intercept form.
recall that the line through (h,k) with slope m is
y-k = m(x-h)
so now just plug in your numbers, then rearrange as desired.
Post your work if you get stuck.
Thank you :)
To write the equation of a line in point-slope form, we need to know the coordinates of a point on the line and its slope. In this case, the given point is (-3, -1) and the slope is 2/3.
The point-slope form of a linear equation is y - y1 = m(x - x1), where (x1, y1) are the coordinates of a point on the line, and m is the slope.
Substituting the values into the point-slope form, we get:
y - (-1) = (2/3)(x - (-3))
Simplifying, we have:
y + 1 = (2/3)(x + 3)
To write the equation in slope-intercept form, which is in the form of y = mx + b, where m is the slope and b is the y-intercept, we need to isolate y.
First, distribute the (2/3) to (x + 3):
y + 1 = (2/3)x + 2
Next, subtract 1 from both sides to isolate y:
y = (2/3)x + 2 - 1
y = (2/3)x + 1
Therefore, the equation of the line in slope-intercept form is y = (2/3)x + 1.