Write an equation of the line with the given slope and containing given points. Slope intercept form
Slope 4 through (-3, 3)
Slope intercept form is
y=mx+b
m- slope
b- y-intercept
To finish this problem, you have to find what the y-intercept is. Just put in what you know first, and try to figure out b.
3=4(-3)+b
3= -12 =b
+12 +12
15=b
You can know see that 15 is b, and you can fill in the slope intercept form.
y=4x+15
I hope this helps :)
y=mx+b
y=4x+b
to solve b, put the point (-3,3) in the equation, solve for b.
Thanks
To write an equation of a line in slope-intercept form, which is y = mx + b, you need to know the slope (m) and a point that the line passes through (x, y).
Given that the slope is 4 and the line passes through (-3, 3), we can substitute these values into the equation.
First, we can plug in the slope (m) into the equation:
y = 4x + b
Next, we can plug in the x-coordinate (-3) and y-coordinate (3) of the given point into the equation to find the y-intercept (b):
3 = 4(-3) + b
3 = -12 + b
b = 3 + 12
b = 15
Now we have the slope (4) and the y-intercept (15), so we can write the equation in slope-intercept form:
y = 4x + 15
Therefore, the equation of the line with slope 4 and passing through the point (-3, 3) in slope-intercept form is y = 4x + 15.