What is the binding energy of 1 mole of 239/94 Pu if the mass defect is 0.001896 kg/mol
E = mc^2 = 0.001896 kg/mol*(3E8 m/s)^2 = 1.7064E14 J/mol
Notice that I used 3E8 m/s for c but mass has more significant figurs to it. For c 3E8 is in round numbers. You may want to look up the speed of light. I think it is 2.9979E8 m/s. That will changae the final answer slightly.
To calculate the binding energy of 1 mole of a nucleus, you can use Einstein's equation, E = mc², where E represents the energy, m is the mass defect, and c is the speed of light.
First, determine the mass equivalent of the mass defect for 1 mole of the nucleus. The mass defect is given as 0.001896 kg/mol.
Next, multiply the mass defect by the speed of light squared (c²). The speed of light is approximately 3 x 10^8 m/s.
E = (0.001896 kg/mol) × (3 x 10^8 m/s)²
Now, calculate the binding energy:
E = 0.001896 kg/mol × (3 x 10^8 m/s)²
E = 0.001896 kg/mol × (9 x 10^16 m²/s²)
E = 1.7064 x 10^14 kg·m²/s²
The binding energy of 1 mole of 239/94 Pu is approximately 1.7064 x 10^14 kg·m²/s².