Calculate the binding energy in Mev of carbon-14 nucleus with a mass defect of 0.109736u.
as Einstein said ... e = m c^2
1 amu results in 931.5 Mev
To calculate the binding energy (BE) of a nucleus using its mass defect, we can use the Einstein's mass-energy equivalence equation, E = mc^2.
The mass defect (Δm) is the difference between the measured mass of a nucleus and the sum of the masses of its individual protons and neutrons. In this case, the mass defect (Δm) is given as 0.109736u.
To convert the mass defect into energy units (MeV), we need to multiply it by the speed of light squared (c^2), which is approximately 931.5 MeV/u (MeV per atomic mass unit).
So, the binding energy (BE) can be calculated as follows:
BE = Δm * c^2
BE = 0.109736u * 931.5 MeV/u
BE ≈ 102.053 MeV
Therefore, the binding energy of the carbon-14 nucleus with a mass defect of 0.109736u is approximately 102.053 MeV.