25.0ml of an unknown concentration of h2so4 are titrated to an endpoint with 47.0 ml of 2.5 m naoh. what is the molarity of the acid
You need to learn the difference between lower and upper case letters. CO is carbon monoxide, Co is cobalt, co is company. m stands for molality. M stands for molarity = M.
H2SO4 + 2NaOH --> Na2SO4 + 2H2O
mols NaOH = M x L =2.5 M x 0.047 = 0,1175
Convert mols NaOH to mols H2SO4. 0.1175 mols NaOH x (1 mol H2SO4/2 mols NaOH) = 0.1175 x 1/2 = 0.0588.
Then M H2SO4 = mols/L = 0.0588/0.025 = ?
To find the molarity of the acid (H2SO4), we can use the equation:
Molarity of acid x Volume of acid = Molarity of base x Volume of base
Let's plug in the given values into the equation:
Molarity of acid x 25.0 ml = 2.5 M x 47.0 ml
Now, let's solve for the molarity of the acid:
Molarity of acid = (2.5 M x 47.0 ml) / 25.0 ml
Molarity of acid ≈ 4.7 M
Therefore, the molarity of the acid (H2SO4) is approximately 4.7 M.
To find the molarity of the acid (H2SO4) solution, we can use the concept of stoichiometry and the balanced equation of the reaction between H2SO4 and NaOH.
The balanced chemical equation for the reaction is:
H2SO4 + 2NaOH -> Na2SO4 + 2H2O
From the equation, we can see that it takes 1 mole of H2SO4 to react with 2 moles of NaOH.
First, let's calculate the moles of NaOH used in the titration:
Moles of NaOH = Molarity of NaOH x Volume of NaOH
Moles of NaOH = 2.5 mol/L x 0.047 L
Moles of NaOH = 0.1175 moles
Since the reaction is 1:2 between H2SO4 and NaOH, the moles of H2SO4 will be twice the moles of NaOH used.
Moles of H2SO4 = 2 x 0.1175 moles
Moles of H2SO4 = 0.235 moles
Now let's calculate the molarity of the H2SO4 solution:
Molarity of H2SO4 = Moles of H2SO4 / Volume of H2SO4 (in liters)
Given that the volume of H2SO4 is 25.0 ml, we need to convert it to liters:
Volume of H2SO4 (in liters) = 25.0 ml / 1000
Volume of H2SO4 (in liters) = 0.025 L
Molarity of H2SO4 = 0.235 moles / 0.025 L
Molarity of H2SO4 = 9.4 mol/L
So, the molarity of the H2SO4 solution is 9.4 mol/L.