Calculate the percent concentration of 3.25ml of H2SO4 dissolve in 68.0ml water
To calculate the percent concentration of H2SO4, we need to know the amount of H2SO4 in grams and the total volume of the solution in milliliters.
First, we need to convert 3.25ml of H2SO4 to grams. We can do this by using the density of H2SO4, which is 1.84 g/mL:
Mass of H2SO4 = volume x density
Mass of H2SO4 = 3.25 mL x 1.84 g/mL
Mass of H2SO4 = 5.98 g
Next, we need to calculate the total volume of the solution, which is the sum of the volumes of water and H2SO4:
Total volume = 3.25 mL + 68.0 mL
Total volume = 71.25 mL
Now we can calculate the percent concentration of H2SO4 by dividing the mass of H2SO4 by the total volume of the solution and multiplying by 100:
Percent concentration = (mass of H2SO4 / total volume) x 100
Percent concentration = (5.98 g / 71.25 mL) x 100
Percent concentration = 8.4%
Therefore, the percent concentration of 3.25 mL of H2SO4 dissolved in 68.0 mL water is 8.4%.
To calculate the percent concentration of a solution, you need to know the amount of solute (H2SO4) and the total volume of the solution.
The amount of solute (H2SO4) is given as 3.25 ml, and the total volume of the solution is the sum of the solute volume and the volume of water, which is 68.0 ml.
To find the percent concentration, follow these steps:
Step 1: Calculate the total volume of the solution:
Total volume = Volume of H2SO4 + Volume of water
Total volume = 3.25 ml + 68.00 ml
Total volume = 71.25 ml
Step 2: Calculate the percent concentration:
Percent concentration = (Volume of H2SO4 / Total volume) x 100
Percent concentration = (3.25 ml / 71.25 ml) x 100
Percent concentration = 0.045 x 100
Percent concentration = 4.5%
Therefore, the percent concentration of 3.25 ml of H2SO4 dissolved in 68.0 ml of water is 4.5%.