Jinil had 6 packs of pencils, and each pack was 2/5 full. Laura had 8 packs of pencils, each 1/4 full. Who had more pencils? How many packs more?
I think Jinil has more but I don't know how many packs he had more I don't know how to do that.
it doesn't make sense to me because he has 6 packs and she has 8 so he cant have more
Better to ask how many PENCILS more?
6 * .4 = 2.4 per pack * 6 = ?
8 * 1/4 = 2 per pack * 8 = ?
This question is so confusing I don't understand it and its driving me nuts.
To solve this problem, we need to compare the total number of pencils Jinil and Laura have.
To find the number of pencils in each pack, we need to multiply the fraction of each pack that is full by the total number of pencils in each pack.
For Jinil:
Each pack is 2/5 full, so the number of pencils in each pack is 2/5 x total pencils per pack.
For Laura:
Each pack is 1/4 full, so the number of pencils in each pack is 1/4 x total pencils per pack.
Since the total number of packs Jinil and Laura have is different, we need to convert the two fractions into the same denominator so that we can compare them directly.
The least common denominator (LCD) for 5 and 4 is 20, so we can rewrite the fractions with this denominator:
Jinil: (2/5) x (20/20) = 40/100
Laura: (1/4) x (20/20) = 20/100
Now, we can compare the two fractions directly to determine who has more pencils.
Jinil has 40/100 of the total number of pencils, and Laura has 20/100 of the total number of pencils.
To find out how many pencils each person has, we need to know the total number of pencils in one pack. Once we have that information, we can multiply the above fractions by the total number of packs each person has.
After that, we can compare the two totals to determine who has more pencils, and the difference between the two totals will give us the number of packs that person has more.
Could you provide the total number of pencils in one pack for both Jinil and Laura?