Jinil had 6 packs of pencils, and each pack was 2/5 full. Laura had 8 packs of pencils, each 1/4 full. Who had more pencils? How many packs more?
I think Jinil has more but I don't know how many packs he had more I don't know how to do that.
it doesn't make sense to me because he has 6 packs and she has 8 so he cant have more
Do not repeat the same post. It just wastes our time going over the repeated post.
See your first post.
To determine who had more pencils, we need to compare the total number of pencils each person had.
To find the number of pencils Jinil had, we multiply the number of packs he had by the fraction that represents the amount each pack was filled:
Jinil's pencils = 6 packs * (2/5)
= (6/1) * (2/5)
= 12/5
To find the number of pencils Laura had, we multiply the number of packs she had by the fraction that represents the amount each pack was filled:
Laura's pencils = 8 packs * (1/4)
= (8/1) * (1/4)
= 2
Comparing the two totals, we see that Jinil had more pencils:
Jinil's pencils = 12/5
Laura's pencils = 2
Since Jinil had more pencils, we can calculate how many packs more he had using the following steps:
1. Find the difference in the total number of pencils between Jinil and Laura:
Difference = Jinil's pencils - Laura's pencils
= (12/5) - 2
= (12/5) - (10/5)
= 2/5
2. Divide the difference by the amount of pencils in each pack to find the number of packs more Jinil had:
Number of packs more = Difference / (2/5)
= (2/5) รท (2/5)
= (2/5) * (5/2)
= 1
Therefore, Jinil had 1 pack more of pencils than Laura.