Willy bought 15 pears and Jack bought 18 oranges. They spent the same amount of money. The difference in cost between a pear and an orange was $0.10. How much did Willy spend on the 15 pears?
1 orange + $0.10
(1 orange + $0.10) * 15
= 15 pears + ( 15 * $0.10)
= 15 pears + $1.50
15 pears + $1.50 = 18 oranges (Cost of 15 pears = Cost of 18 oranges)
18 oranges - 15 pears = 3 oranges
3 oranges —> $1.50
1 orange —> $0.50
1 pear —> $0.50 + $0.10 = $0.60
15 pears —> $0.60 * 15 = $9
Willy spent $9 on the 15 pears.
15x = 18(x-.10)
x = .60
15*.60 = $9.00
18*.50 = $9.00
To find out how much Willy spent on the 15 pears, we need to figure out the cost of each pear.
We know that the difference in cost between a pear and an orange is $0.10. This means that if we subtract $0.10 from the cost of an orange, we will get the cost of a pear.
Let's assume the cost of an orange is x dollars. Therefore, the cost of a pear would be (x - $0.10) dollars.
Willy bought 15 pears, so the total cost of the pears would be 15 times the cost of a pear, which is 15 * (x - $0.10) dollars.
On the other hand, Jack bought 18 oranges, so the total cost of the oranges would be 18 times the cost of an orange, which is 18x dollars.
The problem states that Willy and Jack spent the same amount of money, so we can set up an equation:
15 * (x - $0.10) = 18x
Now we can solve for x:
15x - $1.50 = 18x
Subtract 15x from both sides:
-$1.50 = 3x
Divide both sides by 3:
-$0.50 = x
So the cost of an orange is -$0.50.
Now we can find out how much Willy spent on the 15 pears by substituting this value into the equation for the cost of a pear:
15 * (-$0.50 - $0.10) = 15 * (-$0.60) = -$9.00
Therefore, Willy spent -$9.00 on the 15 pears.