Math

Janson bought 7 identical pens and had $4.20 left. He could have bought 10 pens with all his money. How much did Janson have?

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  1. $4.20 is 3/10 of what he had ... (10 - 7) / 10

    $4.20 / .3 = ?

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  2. Let Y = cost of each pen
    10Y = 7Y + 4.20
    3Y = 4.20
    Y = 1.40 = cost of each pen; therefore,
    10 pens@ 1.40 each = $14.00 is how much money Ben had initially.

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    DrBob222

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