When lead (IV) oxide is heated with hydrogen, the following reaction occurs:
PbO2(s) + 2H2(g) → Pb(s) 2H2O(g)
This reaction can be used to extract lead from its oxide.
Calculate the atom economy to produce lead.
See the same question just above.
Well, calculating the atom economy is pretty serious business, but don't worry, I'll do my best to keep it light-hearted!
First, we need to determine the molar mass of each compound involved. Let's start with lead (IV) oxide - PbO2.
The atomic mass of lead (Pb) is approximately 207.2 g/mol, and each oxygen (O) atom has a mass of around 16 g/mol. Since there are two O atoms in PbO2, the total molar mass is approximately 207.2 + (2 * 16) = 239.2 g/mol.
Next, we need to calculate the molar mass of lead (Pb). Since there's only one lead atom, it will be the same as the atomic mass, which is 207.2 g/mol.
Now, let's find the atom economy! The atom economy is calculated by dividing the molar mass of the desired product (lead, Pb) by the total molar mass of all reactants and products.
Total molar mass of reactants and products = molar mass of PbO2 + molar mass of H2O = 239.2 + (2 * (2 * 1)) = 243.2 g/mol.
Atom economy = (molar mass of desired product / total molar mass of reactants and products) * 100% = (207.2 / 243.2) * 100% = 85.13%.
So, the atom economy to produce lead using this reaction is approximately 85.13%. Now, isn't that quite a chemical circus act?
To calculate the atom economy, we need to determine the ratio of the number of atoms in the desired product (lead) to the total number of atoms in all the reactants.
The balanced equation for the reaction is:
PbO2(s) + 2H2(g) → Pb(s) + 2H2O(g)
In this reaction, the molar ratio between lead (Pb) and lead(IV) oxide (PbO2) is 1:1. This means that 1 mole of PbO2 will produce 1 mole of Pb.
To calculate the atom economy, we can compare the molar mass of Pb to the molar mass of PbO2:
Molar mass of PbO2 = atomic mass of Pb (207.2 g/mol) + 2 * atomic mass of oxygen (16.00 g/mol) = 239.2 g/mol
The atom economy can then be calculated using the formula:
Atom Economy = (molar mass of desired product / molar mass of all reactants) * 100
In this case, the desired product is lead (Pb), so the molar mass of the desired product is 207.2 g/mol.
Atom Economy = (207.2 g/mol / 239.2 g/mol) * 100 = 86.4%
Therefore, the atom economy to produce lead from lead(IV) oxide using this reaction is 86.4%.
To calculate the atom economy, we need to consider the molar masses of the reactants and products involved in the reaction.
1. Start by determining the molar mass of each compound:
- Molar mass of PbO2 = atomic mass of Pb (207.2 g/mol) + (2 * atomic mass of O (16.00 g/mol)) = 239.2 g/mol
- Molar mass of H2 = atomic mass of H (1.008 g/mol) * 2 = 2.016 g/mol
- Molar mass of Pb = 207.2 g/mol
- Molar mass of H2O = atomic mass of H (1.008 g/mol) * 2 + atomic mass of O (16.00 g/mol) = 18.02 g/mol
2. Determine the total molar mass of the reactants:
- Total molar mass of reactants = molar mass of PbO2 + 2 * molar mass of H2 = 239.2 g/mol + 2 * 2.016 g/mol = 243.232 g/mol
3. Determine the total molar mass of the products:
- Total molar mass of products = molar mass of Pb + 2 * molar mass of H2O = 207.2 g/mol + 2 * 18.02 g/mol = 243.24 g/mol
4. Calculate the atom economy using the following formula:
Atom economy = (total molar mass of products / total molar mass of reactants) * 100
Atom economy = (243.24 g/mol / 243.232 g/mol) * 100 ≈ 100.003%
Therefore, the atom economy to produce lead using this reaction is approximately 100.003%.