15.0g of potassium trioxochlorate (v) was crushed and heated with 0.1g of manganese (iv)oxide in it. Write an equation for the reaction and state the role of manganese (iv) oxide in it.
2KClO3 ==> 2KCl + 3O2
MnO2 is a catalyst.Its purpose is to cause the reaction to occur at a lower temperature. MnO2 is not consumed in the reaction.
The IUPAC name for KClO3 is potassium chlorate.
Calculate the volume of gas at stp.
Well, it seems like potassium trioxochlorate (V) and manganese (IV) oxide are having a little party in the test tube! Let's see what they're up to:
The equation for the reaction can be written as:
2KClO₃ + 3MnO₂ → 2KCl + 3MnO₃
Now, let's talk about the role of manganese (IV) oxide. It acts as a catalyst in this reaction! Just like a party DJ, it helps speed things up without getting consumed itself. So, manganese (IV) oxide is like the life of the party, ensuring that the reaction happens faster.
To write the equation for the reaction and determine the role of manganese (IV) oxide, we need to understand the reactants and products involved.
The reactants are potassium trioxochlorate (V) and manganese (IV) oxide. The products of the reaction will depend on the specific chemical properties of these substances.
First, let's identify the chemical formulas for the reactants:
- Potassium trioxochlorate (V): KClO₃
- Manganese (IV) oxide: MnO₂
Now, let's determine the role of manganese (IV) oxide in the reaction.
Manganese (IV) oxide is a powerful oxidizing agent, meaning it can facilitate oxidation reactions by transferring oxygen atoms. In this reaction, it allows the oxidation of chloride ions (Cl⁻) in the potassium trioxochlorate (V).
The balanced equation for the reaction between potassium trioxochlorate (V) and manganese (IV) oxide can be written as follows:
3KClO₃ + 2MnO₂ → 3KCl + 2MnO₄ + 2O₂
In this equation:
- Potassium trioxochlorate (V) (KClO₃) reacts with manganese (IV) oxide (MnO₂).
- The reactants undergo a chemical change, resulting in the formation of potassium chloride (KCl), manganese (IV) oxide (MnO₄), and oxygen gas (O₂).
Therefore, the role of manganese (IV) oxide in this reaction is to act as an oxidizing agent, facilitating the oxidation of chloride ions in potassium trioxochlorate (V).