Question

A 0.400 kg sample of aluminum (c = 9.20 x 102 J/kg°C) at 95.0 °C is dropped into a

0.550 kg pot of water which is at 18.0 °C. What temperature will the mixture come
to?

Answer 1

0.400 * 9.20 *10^2 * (95-T) = 0.550 * Cwater * (T-18)