A sample of aluminum increases its temperature from 20.1oC to 162.5oC by
absorbing 2175 J of heat. What is the mass of the aluminum sample?
(cAl = 0.900 J/goC)
q = mass Al x specific heat Al x (Tfinal-Tinitial)
2175 = mass Al x 0.900 x (162.5 - 20.1)
To find the mass of the aluminum sample, we can use the formula:
q = m * c * ΔT
Where:
q is the heat absorbed by the aluminum sample (in Joules)
m is the mass of the aluminum sample (in grams)
c is the specific heat capacity of aluminum (in J/goC)
ΔT is the change in temperature of the aluminum sample (in oC)
Given:
q = 2175 J
c = 0.900 J/goC
ΔT = (162.5 - 20.1) = 142.4 oC
Now, we can rearrange the formula to solve for the mass (m):
m = q / (c * ΔT)
Substituting the given values:
m = 2175 J / (0.900 J/goC * 142.4 oC)
m ≈ 17.92 grams (rounded to two decimal places)
Therefore, the mass of the aluminum sample is approximately 17.92 grams.
To find the mass of the aluminum sample, you can use the formula:
Q = mcΔT
where:
Q is the heat absorbed by the aluminum sample,
m is the mass of the sample,
c is the specific heat capacity of aluminum, and
ΔT is the change in temperature.
In this case, the heat absorbed by the aluminum sample is given as 2175 J, the specific heat capacity of aluminum (c) is given as 0.900 J/goC, and the change in temperature (ΔT) is the difference between the final and initial temperatures: ΔT = 162.5oC - 20.1oC.
Let's calculate the mass of the aluminum sample:
First, calculate ΔT:
ΔT = 162.5oC - 20.1oC = 142.4oC
Now, rearrange the formula to solve for mass (m):
m = Q / (c * ΔT)
Substitute the given values into the equation:
m = 2175 J / (0.900 J/goC * 142.4oC)
Cancel out the units:
m = 2175 goC / (0.900 J * 142.4oC)
Now calculate the mass:
m ≈ 17.93 grams
Therefore, the mass of the aluminum sample is approximately 17.93 grams.