What mass of aluminum would be in a 65.82 g sample of aluminum oxide?
To find the mass of aluminum in a sample of aluminum oxide, we need to first determine the molar mass of aluminum oxide (Al2O3) and then calculate the mass of aluminum in that sample.
Molar mass of Al2O3:
- Aluminum (Al) has a molar mass of 26.98 g/mol.
- Oxygen (O) has a molar mass of 16.00 g/mol.
The molar mass of Al2O3 is:
2(26.98) + 3(16.00) = 54.06 + 48.00 = 102.06 g/mol
Now, we need to calculate the mass of aluminum in a 65.82 g sample of Al2O3:
(2)(26.98 g/mol) / (102.06 g/mol) x 65.82 g = 34.64 g
Therefore, there would be 34.64 g of aluminum in a 65.82 g sample of aluminum oxide.