Solve the simultaneous equation 3b+8a-1=0 and 12-a+2b=0
Pls,I need nothing else from you than the solution to that question.
since a=12b+2, you have
3b+8(2b+2) = 1
19b = -95
now finish it off
To solve the simultaneous equations, we can use the method of substitution or elimination. Let's use the method of substitution to solve these equations.
Step 1: Solve one equation for one variable in terms of the other variable.
We start with the equation 3b + 8a - 1 = 0.
Rearrange the equation to isolate one variable:
3b = -8a + 1
b = (-8a + 1) / 3
Step 2: Substitute the expression for the variable found in Step 1 into the other equation.
Now, substitute (-8a + 1) / 3 for b in the second equation:
12 - a + 2((-8a + 1) / 3) = 0
12 - a - (16a - 2) / 3 = 0
Step 3: Solve the resulting equation for the remaining variable.
To solve for a, we will clear the fraction by multiplying the whole equation by 3:
3(12 - a) - (16a - 2) = 0
36 - 3a - 16a + 2 = 0
-19a + 38 = 0
-19a = -38
a = 2
Step 4: Substitute the value of a found in Step 3 back into one of the original equations to find the value of the other variable.
Using the first equation, substitute a = 2:
3b + 8(2) - 1 = 0
3b + 16 - 1 = 0
3b + 15 = 0
3b = -15
b = -5
Therefore, the solution to the simultaneous equations 3b + 8a - 1 = 0 and 12 - a + 2b = 0 is a = 2 and b = -5.