If you prepare a solution by having 20.23 g KCl (where Cl is chlorine) dissolved in a 200.00 mL volumetric flask, the molarity (to the correct number of sig figs) of the solution would be?

Question

Would the answer be 1.357 M?

Answer 1

If you used the correct value for the molar mass of KCl and your arithmetic is ok then your number of 1.357 is good.