How many grams of KCl are needed to prepare 125ml of a 0.702M KCl solution?
Ah, chemistry jokes! They never get old. Well, even a Clown Bot can crunch some numbers. To calculate the amount of KCl needed, we first need to determine the number of moles of KCl in 0.125 liters (125 mL) of the solution.
Using the formula: moles = concentration × volume, we can express the volume in liters to match the concentration units.
0.702 mol/L × 0.125 L = 0.08775 moles of KCl
Next, we need to convert moles to grams. The molar mass of KCl is approximately 74.55 g/mol.
0.08775 moles × 74.55 g/mole = 6.53 grams of KCl
So, you will need approximately 6.53 grams of KCl to prepare your solution. Don't worry, this isn't a chemistry lab. No lab coats or safety goggles required!
To calculate the number of grams of KCl needed to prepare a certain volume of a given concentration, we can use the formula:
moles of solute = concentration x volume
First, let's convert the given volume to liters:
125 ml = 125/1000 = 0.125 L
Next, substitute the given values into the formula:
moles of KCl = 0.702 mol/L x 0.125 L
Now we can calculate the moles of KCl:
moles of KCl = 0.08775 mol
Finally, we need to convert moles to grams using the molar mass of KCl. The molar mass of KCl is 39.10 g/mol for potassium (K) and 35.45 g/mol for chlorine (Cl). Adding them together, we get:
molar mass of KCl = 39.10 g/mol + 35.45 g/mol = 74.55 g/mol
Now, we can calculate the grams of KCl:
grams of KCl = moles of KCl x molar mass of KCl
grams of KCl = 0.08775 mol x 74.55 g/mol
Therefore, approximately 6.54 grams of KCl are needed to prepare a 125 ml 0.702 M KCl solution.
To find out how many grams of KCl are needed to prepare a 125 mL solution of 0.702 M KCl, you need to use the formula:
moles = concentration × volume (in liters)
First, convert the volume from milliliters to liters:
125 mL ÷ 1000 mL/L = 0.125 L
Now, use the formula to find the number of moles:
moles = 0.702 M × 0.125 L = 0.08775 moles
The molar mass of KCl is 74.5513 g/mol (39.0983 g/mol for K + 35.453 g/mol for Cl), so you can calculate the mass:
mass = moles × molar mass = 0.08775 moles × 74.5513 g/mol = 6.53 grams
Therefore, you would need approximately 6.53 grams of KCl to prepare a 125 mL solution of 0.702 M KCl.