balance:
Cr(OH)3+Na2O2---- Na2CrO4+H2O+NaOH
Answer. 2 Cr(OH)3 + 3 Na2O2 = 2 Na2CrO4 + 2 H2O + 2 NaOH
The balanced chemical equation you provided is:
Cr(OH)3 + Na2O2 → Na2CrO4 + H2O + NaOH
To balance this equation, we need to make sure that there are the same number of atoms of each element on both sides of the equation.
Here's the step-by-step process to balance this chemical equation:
Step 1: Count the number of atoms of each element on both sides of the equation.
Cr(OH)3: 1 Cr, 3 O, 3 H
Na2O2: 2 Na, 2 O
Na2CrO4: 2 Na, 1 Cr, 4 O
H2O: 2 H, 1 O
NaOH: 1 Na, 1 O, 1 H
Step 2: Balance the atoms of elements that appear in more than one compound.
Start with the elements that appear in the fewest compounds: Cr, H, and Na.
In the reactant side (left):
Cr: 1 Cr → In the product side, we have 1 Cr in Na2CrO4, so it is already balanced.
Now let's move to hydrogen (H):
H: 3 H in Cr(OH)3 → Since 1 H comes from H2O and 1 H comes from NaOH, we need 1 more H. We can balance it by placing a coefficient of 6 in front of H2O and NaOH.
The balanced equation now looks like this:
Cr(OH)3 + Na2O2 → Na2CrO4 + 6H2O + 6NaOH
Next, let's balance sodium (Na):
Na: 2 Na in Na2O2 → In the product side, we have 1 Na in Na2CrO4 and 6 Na in NaOH. So, we need 7 Na in total. We can balance it by placing a coefficient of 7/2 (or 3.5) in front of Na2O2.
The final balanced equation is:
2Cr(OH)3 + 7Na2O2 → 6Na2CrO4 + 6H2O + 6NaOH