Is Na2O2 (sodium peroxide) a polar or non polar? Also, what the electronegativity of the following compounds: H2SO4, HNO3, NA2O2 and HClO3

I think Na2O2 is an ionic compound and certainly polar. As for the electronegativity (EN) of the COMPOUNDS, compounds don't have EN. Elements do. You could be talking about oxidation number or EN. For example EN for H is about 2.2, S is 2.58, O is 3.44 in H2SO4 while oxidation numbers are 1+ for H, 6+ for S and 2- for O in H2SO4.

Na2O2 (sodium peroxide) is a polar compound.

To determine the polarity of a compound, we need to examine the electronegativity difference between the atoms involved. In general, if the electronegativity difference is between 0.5 and 1.7, the bond is considered polar.

Now let's determine the electronegativity of the elements in each compound:

- H2SO4 (sulfuric acid): Hydrogen (H) has an electronegativity of 2.20, sulfur (S) has an electronegativity of 2.58, and oxygen (O) has an electronegativity of 3.44. The electronegativity difference between H and S is 0.38 (non-polar), between S and O is 0.86 (polar), and between O and H is 1.24 (polar). So, H2SO4 is a polar compound.

- HNO3 (nitric acid): Hydrogen (H) has an electronegativity of 2.20, nitrogen (N) has an electronegativity of 3.04, and oxygen (O) has an electronegativity of 3.44. The electronegativity difference between H and N is 0.84 (polar), between N and O is 0.40 (non-polar), and between O and H is 1.24 (polar). So, HNO3 is a polar compound.

- Na2O2 (sodium peroxide): Sodium (Na) has an electronegativity of 0.93, and oxygen (O) has an electronegativity of 3.44. The electronegativity difference between Na and O is 2.51, which is more than 1.7. So, Na2O2 is a polar compound.

- HClO3 (chloric acid): Hydrogen (H) has an electronegativity of 2.20, chlorine (Cl) has an electronegativity of 3.16, and oxygen (O) has an electronegativity of 3.44. The electronegativity difference between H and Cl is 0.96 (polar), between Cl and O is 0.28 (non-polar), and between O and H is 1.24 (polar). So, HClO3 is a polar compound.

In summary:
- H2SO4 is a polar compound.
- HNO3 is a polar compound.
- Na2O2 is a polar compound.
- HClO3 is a polar compound.

To determine whether a molecule is polar or nonpolar, you need to consider its molecular geometry and the polarity of each bond within the molecule.

For Na2O2 (sodium peroxide), let's first determine its Lewis structure. Sodium (Na) has a +1 charge and oxygen (O) has a -2 charge. So, in the compound Na2O2, each sodium atom donates one electron and each oxygen atom gains two electrons in order to achieve a stable configuration.

The Lewis structure for Na2O2 can be written as follows:

O-Na=O

Since all atoms in the molecule are connected by single bonds, the molecular geometry of Na2O2 is linear. The oxygen atoms are the more electronegative elements in the molecule, so they will exert a stronger pull on the shared electrons in the O-Na bonds. This creates a separation of charge within the molecule, resulting in a polar molecule.

Now, let's consider the electronegativity of the other compounds you mentioned:

- H2SO4 (sulfuric acid): Hydrogen (H) has an electronegativity of about 2.2, sulfur (S) has an electronegativity of about 2.58, and oxygen (O) has an electronegativity of about 3.44. Since the sulfur-oxygen (S-O) bonds are polar, the molecule H2SO4 is polar.

- HNO3 (nitric acid): Hydrogen (H) has an electronegativity of about 2.2, nitrogen (N) has an electronegativity of about 3.04, and oxygen (O) has an electronegativity of about 3.44. Since the nitrogen-oxygen (N-O) bonds are polar, the molecule HNO3 is polar.

- HClO3 (chloric acid): Hydrogen (H) has an electronegativity of about 2.2, chlorine (Cl) has an electronegativity of about 3.16, and oxygen (O) has an electronegativity of about 3.44. Since the chlorine-oxygen (Cl-O) bonds are polar, the molecule HClO3 is polar.

In summary, Na2O2 is a polar molecule, while H2SO4, HNO3, and HClO3 are also polar molecules due to the presence of polar bonds within them.