In trangle abc a=29,b=36,b=15.8cm find a. thank you
Please solve.the question
Please check what you typed. You have two sides called b.
since you specify that b=15.8 cm, I assume that you meant angles
A=29° and B=36°
If so, then use the law of sines to get
a/sinA = b/sinB
You need to pay attention to your labels. The triangle is usually named by its angles, in Upper Case.
If it is angle A you want and c = 15.8 then
a*2 = 841
b^2 = 1296
c^2 = 249.64
a^2 = b^2 + c^2 - 2 b c cos A (law of cosines)
841 = 1296 + 249.64 - 2 * 36 * 15.8 cos A
To find side a of triangle ABC, you will need to use the information given:
Given:
Side b = 36 cm
Side c = 15.8 cm
To find side a, you can use the law of cosines, which states:
c² = a² + b² - 2ab * cos(C)
In this case, we have to rearrange the formula to solve for side a:
a² = c² - b² + 2ab * cos(C)
Now, substitute the given values into the formula:
a² = (15.8)² - (36)² + 2(15.8)(36) * cos(C)
To proceed, we need to know the measure of angle C in triangle ABC. The information given does not provide the angle measure, so it is not possible to directly solve for side a without additional information.
If you have the angle measure, you can substitute it into the equation above and solve for side a using a scientific calculator or trigonometric tables.