Construct triangle ABC=12cm,AC=8cm and BAC =30⁰
what does "ABC=12cm" even mean?
The height of the triangle is 6 cm.
The length of side BC is 10 cm.
To construct triangle ABC with the given measurements and angle:
1. Draw a straight line segment AB of length 12 cm.
2. Place the compass pointer at point A and set the width to 8 cm.
3. Draw an arc on one side of AB to intersect the line segment.
4. Keep the compass width the same, place the pointer on the new intersection point, and draw another arc.
5. Label the point of intersection between the two arcs as C.
6. Draw the line segment AC and label it as such.
7. Place the compass pointer at point B and set the width to any length.
8. Draw an arc that intersects AC (created in step 6), and label the point of intersection as D.
9. Draw the line segments CD and BD to complete the triangle.
10. Label the vertices as A, B, and C.
You now have triangle ABC with side lengths AB = 12 cm, AC = 8 cm, and angle BAC = 30 degrees.
To construct triangle ABC with the given information, follow these steps:
Step 1: Start by drawing a straight line segment AB of length 12 cm. This will serve as the base of the triangle.
Step 2: From point A, use a compass to draw an arc with a radius of 8 cm to intersect the line segment AB. Label this point of intersection as C.
Step 3: Use a protractor to measure BAC with an angle of 30 degrees. Starting from point A, measure 30 degrees and mark the point as point D on line segment AB.
Step 4: Join points B and C by drawing a straight line segment BC.
Step 5: Label the points as A, B, and C to complete triangle ABC.
Now, you have successfully constructed triangle ABC with side lengths AB measuring 12 cm, AC measuring 8 cm, and angle BAC measuring 30 degrees.