Hot Steel; Cold Ice: A 36.0 g block of ice sits at −50.0 °C under 1.00 atm constant pressure in a perfectly insulated container. A 225 g mass of stainless steel at 125 °C is dropped onto the ice, and the system is closed. When the system reaches thermal equilibrium, ice remains.
What is the value of q_steel? Enter your answer in Celsius using no decimal places?
How about sharing the specific heat of ice and that of stainless steel with us?
delta H fus (H2o) = 333 j/g
delta H vap (H2o) = 2260 J/g
Cp (steel) = 0.500 J g^-1°C^-1
S(H2o(s)) = 2.11 J g^-1 °C^-1
S (H2o(f)) =4.18J g^-1 °C^-1
S (H2o(g)) = 2.00 J g^-1 °C^-1
Dr. Bob help me :(((
I'm confused with q_steel. I would think q stands for joules of heat but in degrees C?
Clarify the question please.
To determine the value of q_steel, we need to calculate the heat transfer in the steel as it cools down to reach the thermal equilibrium with the ice.
The heat transfer can be calculated using the equation:
q = m * c * ΔT
where:
q represents the heat transfer
m represents the mass of the object
c represents the specific heat capacity of the material
ΔT represents the change in temperature
First, let's calculate the change in temperature of the steel. The initial temperature of the steel is 125 °C, and it reaches the thermal equilibrium with the ice, which is at -50.0 °C. Therefore, the change in temperature is:
ΔT = final temperature - initial temperature
ΔT = (-50.0 °C) - (125 °C)
ΔT = -175 °C
Next, we need to determine the specific heat capacity of stainless steel. The specific heat capacity of stainless steel is approximately 0.51 J/g°C.
Now, we can calculate the heat transfer in the steel:
q_steel = m * c * ΔT
q_steel = (225 g) * (0.51 J/g°C) * (-175 °C)
Calculating this expression gives us the value of q_steel in joules (J). However, the question asks for the answer in Celsius (°C). To convert the joules to Celsius, we need to convert it to calories by dividing the value by 4.18 (1 calorie = 4.18 joules):
q_steel = (225 g) * (0.51 J/g°C) * (-175 °C) / 4.18
Now, we can evaluate this expression to find the value of q_steel in calories (cal).
Please note that in this particular question, the mass of the steel is provided in grams, and the specific heat capacity is given in joules, but the answer is requested in Celsius. To follow the units provided in the question and maintain consistency, the calculation is performed as explained above. However, for accurate calculations, it is recommended to convert all units to one system (e.g., grams and joules).