Am re-posting this question.A certain volume of oxgen diffused from a given apparatus in 125 secs.In the same conditions,the same volume of gas N,diffused in 100 secs.Calculate the RMM.I used graham's law but i think i did it the wrong way.Plz help out.
sqrt(N/32)=rateO/rateN=V/125/V/100= 125/100
N= 32*( 1.25)^2= 50
Where does 32 come from
Am sorry i got it
Well Lucy, you did it. I posted you didn't have the right answer and I would be glad to find your error if you posted your solution. You found someone who did your work for you.
Thanku for the concern
To calculate the relative molecular mass (RMM) using Graham's law, you need to consider the rates of diffusion of the two gases. The ratio of the rates of diffusion is inversely proportional to the square root of the ratio of the molar masses.
Here's how you can find the RMM:
1. Make a ratio of the times taken for diffusion: R(N₂)/R(O₂) = 100/125 = 4/5.
2. Square the ratio obtained: (4/5)² = 16/25.
3. As per Graham's law, the rate of diffusion is inversely proportional to the square root of the molar mass. So, we have (R(N₂)/R(O₂))² = (M(O₂)/M(N₂)) = 16/25.
4. Rearrange the equation to solve for the RMM: M(N₂) = (M(O₂) * 25) / 16.
5. You'll need to know the RMM of oxygen to continue. The RMM of oxygen is 32 g/mol.
6. Substitute the known values into the equation: M(N₂) = (32 * 25) / 16 = 50 g/mol.
Therefore, the RMM of gas N₂ is 50 g/mol.
I hope this helps! Let me know if there's anything else I can assist you with.