Consider the reaction H2(g) + I2(g) ---- 2HI(g). What is the reaction quotient, Q, for this system when [H2] = 0.100 M, [I2] = 0.200 M, and [HI] = 3.50 M?
The choices are;
87.5
175
350
613
I dont believe it is 87.5 or 613
it is 613
I wasnt guessing I did the math incorrect
To find the reaction quotient (Q) for this system, you need to write an expression using the concentrations of the reactants and products, just like you would for the equilibrium constant (K).
The balanced chemical equation is: H2(g) + I2(g) --> 2HI(g)
The expression for Q is written as follows:
Q = ([HI]^2) / ([H2] * [I2])
Plugging in the given concentrations: [H2] = 0.100 M, [I2] = 0.200 M, and [HI] = 3.50 M into the expression, we get:
Q = (3.50^2) / (0.100 * 0.200)
= 12.25 / 0.020
= 612.5
Therefore, the reaction quotient (Q) for this system, when the given concentrations are used, is 612.5.
Out of the provided choices, this calculation supports your statement that 87.5 and 613 are not correct.
So you calculated the wrong answer twice.
H2(g) + I2(g) ---- 2HI(g).
Q = (HI)^2/(H2)(I2) = (3.5)(3.5)/(0.1)(0.2)
I think your guess is wrong.
Why did you guess. Plug the numbers into Q and calculate.