balance each reaction and write its reaction quotient CH4(g) + F2(g)-----CF4(g) +HF(g)
CH4(g) + 4F2(g)-----CF4(g) + 4HF(g)
Qc = (CF4)(HF)^4/(CH4)(F2)^4
I chose to write the concentration quotient. There is a pressure quotient.
Qp = same as Qc BUT instead of concentration in moles/L use pressure in atmospheres. It's harder to write this one without subscripts and superscripts.
Qp = pCF4*p^4HF/pCH4*p^4F2
Sure, here's the balanced equation for the reaction:
CH4(g) + 2F2(g) → CF4(g) + 4HF(g)
Now, let's calculate the reaction quotient, Q:
Q = [CF4] * [HF]^4 / [CH4] * [F2]^2
Remember, Q represents the relative concentrations of the products and reactants at a given point during the reaction.
Feel free to plug in the actual concentrations of the molecules to calculate the numerical value of Q!
To balance the given reaction, CH4(g) + F2(g) → CF4(g) + HF(g), we need to ensure that the number of atoms on each side is equal.
Here's how to balance the reaction step-by-step:
1. Count the number of atoms of each element on both sides of the equation:
On the left side:
- Carbon (C): 1 atom
- Hydrogen (H): 4 atoms
- Fluorine (F): 2 atoms
On the right side:
- Carbon (C): 1 atom
- Hydrogen (H): 1 atom
- Fluorine (F): 5 atoms
2. Balance the carbon atoms:
Since both sides have only 1 carbon atom, carbon is already balanced.
3. Balance the hydrogen atoms:
On the left side, there are 4 hydrogen atoms, while on the right side, there is only 1 hydrogen atom. To equalize the number of hydrogen atoms, multiply the HF molecule on the right side by 4:
CH4(g) + F2(g) → CF4(g) + 4HF(g)
4. Balance the fluorine atoms:
On the left side, there are 2 fluorine atoms, while on the right side, there are 4 fluorine atoms from CF4(g) and 4 fluorine atoms from 4HF(g). Thus, there are 8 fluorine atoms in total on the right side. To equalize the number of fluorine atoms, multiply the F2 molecule on the left side by 4:
CH4(g) + 4F2(g) → CF4(g) + 4HF(g)
Now, the balanced equation is:
CH4(g) + 4F2(g) → CF4(g) + 4HF(g)
To write the reaction quotient (Q), you simply write the expression for the concentration of each species involved in the reaction as follows:
Q = [CF4] x [HF]^4 / [CH4] x [F2]^4
To balance the given reaction and write its reaction quotient (Q), follow these steps:
Step 1: Write down the unbalanced chemical equation:
CH4(g) + F2(g) → CF4(g) + HF(g)
Step 2: Count the number of atoms of each element on both sides of the equation. It's usually helpful to start with the elements that appear in the fewest compounds. In this case, we'll begin with fluorine (F) and hydrogen (H).
On the left side: 1 F atom
On the right side: 1 F atom
To balance the F atoms, we need to place a coefficient of 2 in front of the HF product:
CH4(g) + F2(g) → CF4(g) + 2HF(g)
On the left side: 4 H atoms
On the right side: 2 H atoms
To balance the H atoms, we need to place a coefficient of 2 in front of the CH4 reactant:
2CH4(g) + F2(g) → CF4(g) + 2HF(g)
Step 3: Check if all the elements are balanced. In this case, carbon (C) is the only remaining element.
On the left side: 2 C atoms
On the right side: 1 C atom
To balance the C atoms, we need to place a coefficient of 1 in front of the CF4 product:
2CH4(g) + F2(g) → 1CF4(g) + 2HF(g)
Now, the equation is balanced.
Step 4: Write the balanced equation:
2CH4(g) + F2(g) → CF4(g) + 2HF(g)
To find the reaction quotient (Q) for a chemical equation, you need the concentrations (or pressures) of the reactants and products. The Q expression for the given reaction is:
Q = [CF4] * [HF]^2 / [CH4]^2 * [F2]
Note: The square brackets [ ] represent the concentration (or pressure) of each species.
You can calculate the Q value once you have the concentrations of the reactants and products at a given moment.