Sketch the graph of f(x)=x^2-4 and y=1/f(x) on the grid provided. label the asymptotes, the invariant points and the intercepts of y=1/f(x)
notice the asymptotes for y = 1/f(x)
https://www.wolframalpha.com/input/?i=plot+y+%3Dx%5E2-4+%2C+y+%3D+1%2F%28x%5E2-4%29+from+-4+to+4
state the vertex of f(x)=0.2(x-5)^2-8, then graph this function on the grid provided. Label any points you plot with the ordered pair.
The vertex of the function f(x) = 0.2(x-5)^2 - 8 is (5, -8).
Here is the graph of the function:
(Insert graph of f(x) = 0.2(x-5)^2 - 8)
The vertex is located at the point (5, -8).
the equation of Axis of symmetry of f(x)=0.2(x-5)^2-8, then graph this function on the grid provided. Label any points you plot with the ordered pair.
The equation of the axis of symmetry of f(x) = 0.2(x-5)^2 - 8 is x = 5.
Here is the graph of the function:
(Insert graph of f(x) = 0.2(x-5)^2 - 8)
The axis of symmetry is a vertical line passing through x = 5.
determine the y-intercept of f(x)=0.2(x-5)^2-8, then graph this function on the grid provided. Label any points you plot with the ordered pair.
To find the y-intercept of the function f(x) = 0.2(x-5)^2 - 8, we can substitute x = 0 into the equation:
f(0) = 0.2(0-5)^2 - 8
= 0.2(-5)^2 - 8
= 0.2(25) - 8
= 5 - 8
= -3
Therefore, the y-intercept of the function f(x) = 0.2(x-5)^2 - 8 is (0, -3).
Here is the graph of the function:
(Insert graph of f(x) = 0.2(x-5)^2 - 8)
The y-intercept is the point (0, -3).
determine the y-intercept of f(x)=0.2(x-5)^2 -8 in equation.
The y-intercept of a function is the value of y when x is equal to 0. To find the y-intercept of f(x) = 0.2(x-5)^2 -8, we can substitute x = 0 into the equation:
f(0) = 0.2(0-5)^2 -8
= 0.2(-5)^2 -8
= 0.2(25) -8
= 5 -8
= -3
Therefore, the y-intercept of the function f(x) = 0.2(x-5)^2 -8 is -3.