determine the y-intercept of f(x)=0.2(x-5)^2 - 8, then graph this function on the grid provided. Label any points you plot with the ordered pair.
To determine the y-intercept of the function f(x), we substitute x = 0 into the function.
f(x) = 0.2(x-5)^2 - 8
f(0) = 0.2(0-5)^2 - 8
= 0.2(-5)^2 - 8
= 0.2(25) - 8
= 5 - 8
= -3
Therefore, the y-intercept of f(x) is -3.
To graph this function:
1. Set up a coordinate grid.
2. Plot the y-intercept, which is the point (0, -3).
3. Find other points by plugging in different x-values into the equation and calculating their corresponding y-values.
4. Connect the plotted points to form a smooth curve.
The graph should show a downward-opening parabola since the coefficient of the x^2 term is positive.
what is the equation for f(x)=0.2(x-5)^2 - 8
The equation for the function f(x) = 0.2(x-5)^2 - 8 is already provided.
determine the y-intercept of f(x)=0.2(x-5)^2 - 8
To determine the y-intercept of the function f(x) = 0.2(x-5)^2 - 8, we substitute x = 0 into the equation:
f(x) = 0.2(x-5)^2 - 8
f(0) = 0.2(0-5)^2 - 8
= 0.2(-5)^2 - 8
= 0.2(25) - 8
= 5 - 8
= -3
The y-intercept of the function f(x) = 0.2(x-5)^2 - 8 is -3.
equation of axis of symmetry of f(x)=0.2(x-5)^2 - 8
The equation for the axis of symmetry of a quadratic function in the form f(x) = a(x-h)^2 + k is given by x = h.
In this case, the equation f(x) = 0.2(x-5)^2 - 8 is already in the vertex form, where the vertex is located at the point (h, k). Therefore, the axis of symmetry is the vertical line x = 5.
So, the equation of the axis of symmetry of the function f(x) = 0.2(x-5)^2 - 8 is x = 5.
vertex of f(x)=0.2(x-5)^2 - 8
The vertex form of a quadratic function is given by f(x) = a(x-h)^2 + k, where (h, k) represents the coordinates of the vertex.
In the given function f(x) = 0.2(x-5)^2 - 8, we can identify that h = 5 and k = -8.
Therefore, the vertex of the function f(x) = 0.2(x-5)^2 - 8 is (5, -8).