Sketch the graph of the equation. Label the vertex and the intercepts.
yequalsxsquaredminus1
Question content area bottom left
Part 1
Use the graphing tool to graph the equation.
Part 2
The intercept(s) is/are
enter your response here.
(Type an ordered pair. Type an exact answer, using radicals as needed. Use a comma to separate answers as needed.)
Part 1:
The graph of the equation y = x^2 - 1 is a parabola that opens upwards. The vertex is at (0, -1) and the y-intercept is at (0, -1).
Part 2:
The x-intercepts can be found by setting y = 0:
0 = x^2 - 1
x^2 = 1
x = ±1
Therefore, the x-intercepts are at (-1, 0) and (1, 0).