Sketch the graph of f(x)=x^2-4 and y=1/f(x) on the grid provided. label the asymptotes, the invariant points and the intercepts of y=1/f(x)
notice the asymptotes for y = 1/f(x)
https://www.wolframalpha.com/input/?i=plot+y+%3Dx%5E2-4+%2C+y+%3D+1%2F%28x%5E2-4%29+from+-4+to+4
state the vertex of f(x)=0.2(x-5)^2-8, then graph this function on the grid provided. Label any points you plot with the ordered pair.
The vertex of the function f(x) = 0.2(x-5)^2 - 8 is (5, -8).
Here is the graph of the function:
(Insert graph of f(x) = 0.2(x-5)^2 - 8)
The vertex is located at the point (5, -8).
the equation of Axis of symmetry of f(x)=0.2(x-5)^2-8, then graph this function on the grid provided. Label any points you plot with the ordered pair.
The equation of the axis of symmetry of f(x) = 0.2(x-5)^2 - 8 is x = 5.
Here is the graph of the function:
(Insert graph of f(x) = 0.2(x-5)^2 - 8)
The axis of symmetry is a vertical line passing through x = 5.
determine the y-intercept of f(x)=0.2(x-5)^2-8, then graph this function on the grid provided. Label any points you plot with the ordered pair.
To find the y-intercept of the function f(x) = 0.2(x-5)^2 - 8, we can substitute x = 0 into the equation:
f(0) = 0.2(0-5)^2 - 8
= 0.2(-5)^2 - 8
= 0.2(25) - 8
= 5 - 8
= -3
Therefore, the y-intercept of the function f(x) = 0.2(x-5)^2 - 8 is (0, -3).
Here is the graph of the function:
(Insert graph of f(x) = 0.2(x-5)^2 - 8)
The y-intercept is the point (0, -3).
determine the y-intercept of f(x)=0.2(x-5)^2 -8 in equation.
The y-intercept of a function is the value of y when x is equal to 0. To find the y-intercept of f(x) = 0.2(x-5)^2 -8, we can substitute x = 0 into the equation:
f(0) = 0.2(0-5)^2 -8
= 0.2(-5)^2 -8
= 0.2(25) -8
= 5 -8
= -3
Therefore, the y-intercept of the function f(x) = 0.2(x-5)^2 -8 is -3.
the axis of symmetry of f(x)=0.2(x-5)^2 -8 in equation.
The axis of symmetry of a quadratic function is given by the equation x = h, where h is the x-coordinate of the vertex of the parabola.
For the function f(x) = 0.2(x-5)^2 -8, the vertex form is f(x) = a(x-h)^2 + k, where (h, k) is the vertex.
Comparing this with the given function, we can see that the vertex is (5, -8).
Therefore, the equation of the axis of symmetry is x = 5.
determine the y-intercept of f(x)=-1/8(x-7)(x+9), then graph this function on the grid provided. Label any points you plot with the ordered pair.
To find the y-intercept of the function f(x) = -1/8(x-7)(x+9), we can substitute x = 0 into the equation:
f(0) = -1/8(0-7)(0+9)
= -1/8(-7)(9)
= -1/8 * -63
= 63/8
Therefore, the y-intercept of the function f(x) = -1/8(x-7)(x+9) is (0, 63/8).
Here is the graph of the function:
(Insert graph of f(x) = -1/8(x-7)(x+9))
The y-intercept is the point (0, 63/8).
determine the x-intercept of f(x)=-1/8(x-7)(x+9), then graph this function on the grid provided. Label any points you plot with the ordered pair.
To find the x-intercept of the function f(x) = -1/8(x-7)(x+9), we can set y equal to zero and solve for x:
0 = -1/8(x-7)(x+9)
Setting each factor equal to zero:
x-7 = 0 or x+9 = 0
Solving for x:
x = 7 or x = -9
Therefore, the x-intercepts of the function f(x) = -1/8(x-7)(x+9) are (7, 0) and (-9, 0).
Here is the graph of the function:
(Insert graph of f(x) = -1/8(x-7)(x+9))
The x-intercepts are the points (7, 0) and (-9, 0).