A chemist needs to make 750.0 mL of a M solution of sulfuric acid. Looking on the shelves, she finds a bottle of 10.0 M sulfuric acid. How can the desired solution be made?
show work please
You didn't post the molarity. If I guess you want a 2 M and you have a 10.0 M solution on the shelf, you want to dilute it. How much? Use the dilution formula which is
mL1 x M1 = mL2 x M2
mL1 x 10.0 M = 750 mL x 2 M
Solve for mL1. Take that many mL, place it in a 750 mL volumetric flask, and make to the mark, mix thoroughly, stopper, label.
To determine how to make a 750.0 mL M solution of sulfuric acid using a 10.0 M solution, we can use the dilution formula:
M1V1 = M2V2
Where:
M1 = initial concentration of the solution (10.0 M)
V1 = initial volume of the solution (unknown)
M2 = final concentration of the solution (M)
V2 = final volume of the solution (750.0 mL)
First, let's rearrange the formula to solve for V1:
V1 = (M2 * V2) / M1
Substituting the given values into the formula, we get:
V1 = (M2 * V2) / M1
V1 = (M2 * 750.0 mL) / 10.0 M
V1 = (M2 * 75.0 mL) / 1.0
Now let's solve for V1. Assuming we want to make a 1.0 M sulfuric acid solution:
V1 = (1.0 M * 75.0 mL) / 1.0
V1 = 75.0 mL
Therefore, to make a 750.0 mL 1.0 M sulfuric acid solution, you would need to take 75.0 mL of the 10.0 M sulfuric acid solution and dilute it up to a total volume of 750.0 mL with a suitable solvent, such as water.
To make a M (molar) solution of sulfuric acid, you need to determine how much of the 10.0 M sulfuric acid needs to be diluted with water to obtain the desired molarity.
The formula to calculate the volume of concentrated solution required is:
V1 x C1 = V2 x C2
Where:
V1 = volume of concentrated solution
C1 = molarity of concentrated solution
V2 = volume of desired solution
C2 = molarity of desired solution
In this case, we have:
V1 = unknown
C1 = 10.0 M
V2 = 750.0 mL
C2 = Molarity of desired solution (which is not given)
To determine the concentration of the desired solution (C2), we need more information. Once we have an available value for C2, we can plug in the values into the formula mentioned above to find V1.
Assuming the desired molarity (C2) is given as 1.0 M, we can calculate V1 as follows:
V1 = (V2 x C2) / C1
V1 = (750.0 mL x 1.0 M) / 10.0 M
V1 = 75.0 mL
Therefore, to make 750.0 mL of a 1.0 M solution of sulfuric acid, you would measure 75.0 mL of the 10.0 M sulfuric acid and then dilute it with water to obtain the desired volume.