70,0 cm^3 of a sodium hydroxide solution ( concentration = 0,180 mol•dm^-3 ) reacts completely with 30, 0 cm^3 of a sulfuric acid solution. Calculate the concentration of the sulfuric acid solution.
First, calculate the number of moles of sodium hydroxide solution:
Moles = Volume (dm^3) x Concentration (mol•dm^-3)
= 70.0 cm^3 x 0.180 mol•dm^-3
= 12.6 mol
Since the reaction between sodium hydroxide and sulfuric acid is 1:2, the number of moles of sulfuric acid solution is twice the number of moles of sodium hydroxide solution:
Moles of sulfuric acid solution = 2 x Moles of sodium hydroxide solution
= 2 x 12.6 mol
= 25.2 mol
Next, calculate the concentration of the sulfuric acid solution:
Concentration = Moles / Volume (dm^3)
We are given the volume of the sulfuric acid solution as 30.0 cm^3, so we need to convert it to dm^3:
Volume (dm^3) = 30.0 cm^3 / (1000 cm^3/dm^3)
= 0.030 dm^3
Now, calculate the concentration:
Concentration = 25.2 mol / 0.030 dm^3
= 840 mol•dm^-3
Therefore, the concentration of the sulfuric acid solution is 840 mol•dm^-3.
I don't believe it Bot.
Apologies for any confusion. Let's go through the calculations again.
First, calculate the number of moles of sodium hydroxide solution:
Moles = Volume (dm^3) x Concentration (mol•dm^-3)
= 70.0 cm^3 x 0.180 mol•dm^-3
= 12.6 mol
Since the reaction between sodium hydroxide and sulfuric acid is 1:2, the number of moles of sulfuric acid solution is twice the number of moles of sodium hydroxide solution:
Moles of sulfuric acid solution = 2 x Moles of sodium hydroxide solution
= 2 x 12.6 mol
= 25.2 mol
Next, calculate the concentration of the sulfuric acid solution:
Concentration = Moles / Volume (dm^3)
We are given the volume of the sulfuric acid solution as 30.0 cm^3, so we need to convert it to dm^3:
Volume (dm^3) = 30.0 cm^3 / (1000 cm^3/dm^3)
= 0.030 dm^3
Now, calculate the concentration:
Concentration = 25.2 mol / 0.030 dm^3
= 840 mol•dm^-3
Therefore, the concentration of the sulfuric acid solution is 840 mol•dm^-3.
Here is the correct solution.
moles NaOH = M x L = 0.180 x 0.070 = 0.0126
2NaOH + H2SO4 ==> Na2SO4 + 2H2O
Convert moles NaOH to mols H2SO4 this way.
0.0126 mols NaOH x (1 mol H2SO4/2 moles NaOH) = 0.0063
Then M H2SO4 = mols/L = 0.0063 mols/0.030 L = 0.21 M = 0.21 mols/dm^3
Apologies for the previous incorrect response. Thank you for providing the correct solution.
The correct concentration of the sulfuric acid solution is 0.21 mol/dm^3.
To solve this problem, we can first determine the number of moles of sodium hydroxide (NaOH) reacting with sulfuric acid (H2SO4). By using the equation:
NaOH + H2SO4 → Na2SO4 + H2O
We can see that the stoichiometric ratio between NaOH and H2SO4 is 1:2, meaning that one mole of NaOH reacts with two moles of H2SO4.
Given that the concentration of NaOH solution is 0.180 mol/dm^3 and the volume is 70.0 cm^3, we can calculate the number of moles of NaOH:
Moles of NaOH = concentration × volume
= 0.180 mol/dm^3 × 70.0 cm^3 / 1000 cm^3/dm^3
= 0.0126 mol
Since the stoichiometric ratio between NaOH and H2SO4 is 1:2, the number of moles of H2SO4 will be twice the moles of NaOH:
Moles of H2SO4 = 0.0126 mol × 2
= 0.0252 mol
Now that we know the number of moles of H2SO4 reacted, we can calculate the concentration of the sulfuric acid solution by using the equation:
Concentration = moles of solute / volume of solution
Given that the volume of the sulfuric acid solution is 30.0 cm^3, we have:
Concentration = 0.0252 mol / (30.0 cm^3 / 1000 cm^3/dm^3)
= 0.84 mol/dm^3
Therefore, the concentration of the sulfuric acid solution is 0.84 mol/dm^3.
To calculate the concentration of the sulfuric acid solution, we can use the concept of molar ratio and the equation balanced equation between sodium hydroxide (NaOH) and sulfuric acid (H2SO4) to determine the number of moles of sulfuric acid used in the reaction.
The balanced equation for the reaction between NaOH and H2SO4 is:
2NaOH + H2SO4 -> Na2SO4 + 2H2O
From the balanced equation, we can see that 2 moles of NaOH react with 1 mole of H2SO4. So, using the molar ratio, we can calculate the number of moles of H2SO4 used.
Given that the volume of the sodium hydroxide solution is 70.0 cm^3 and the concentration of the sodium hydroxide solution is 0.180 mol•dm^-3, we can calculate the number of moles of NaOH:
Moles of NaOH = Concentration * Volume
= 0.180 mol•dm^-3 * 0.070 dm^3 (convert cm^3 to dm^3)
= 0.0126 moles
According to the balanced equation, the molar ratio between NaOH and H2SO4 is 2:1. Therefore, the number of moles of H2SO4 is half the number of moles of NaOH used:
Moles of H2SO4 = 0.0126 moles / 2
= 0.0063 moles
Now, we need to calculate the concentration of the sulfuric acid solution. We know that 30.0 cm^3 of the sulfuric acid solution completely reacted with the moles of H2SO4 we calculated above.
To find the concentration, we divide the number of moles of sulfuric acid by the volume of the sulfuric acid solution:
Concentration = Moles / Volume
= 0.0063 moles / 0.030 dm^3 (convert cm^3 to dm^3)
= 0.21 mol•dm^-3
Therefore, the concentration of the sulfuric acid solution is 0.21 mol•dm^-3.