Question

what is the concentration of the conjugate acid and conjugate base of a 0.2molar acetate copper with pH of 5.0 and pKa of 4.77

Answer 1

(a) = concentration of acid

(b) = concentration of base
You need to solve two equations simultaneously.
pH = pKa + log ([b)/(a)]
equation 1 is 5.0 = 4.77 + log [(b)/(a)]
Solve for ratio of (b)/(a)
equation 2 is 0.2 M = (a) + (b)
Post your work if you get stuck