What volume of hydrogen is produced at s.t.p when 260g of zinc reacts with excess HCl acid.
write the equation. Each mole of Zn produces 1 mole of H2
So, how many moles of Zn is 260g ?
If there are n moles, then they will occupy 22.4n L of space.
Zn + 2HCl ==> ZnCl2 + H2
mols Zn = grams/atomic mass = 260/65.38 = approx 4 but that's an estimate only.
Convert mols Zn to mols H2 produced. That's 1:1; therefore, mols Zn = mols H2.
You know 1 mol H2 @ stp occupies 22.4 L so
mols H2 x 22.4 = L H2 @ STP.
To calculate the volume of hydrogen gas produced at standard temperature and pressure (STP), we need to use the balanced chemical equation for the reaction between zinc and hydrochloric acid (HCl).
The balanced chemical equation for the reaction is:
Zn + 2HCl -> ZnCl2 + H2
From the equation, we can see that 1 mole of zinc (Zn) reacts with 2 moles of hydrochloric acid (HCl) to produce 1 mole of hydrogen gas (H2).
Step 1: Calculate the number of moles of zinc (Zn) using its molar mass.
The molar mass of zinc (Zn) is 65.38 g/mol.
Number of moles of Zn = mass of Zn / molar mass of Zn
= 260 g / 65.38 g/mol
= 3.97 mol (approx)
Step 2: Determine the number of moles of hydrogen gas (H2) produced using the stoichiometry of the balanced equation.
From the balanced equation, we can see that 1 mole of zinc (Zn) produces 1 mole of hydrogen gas (H2).
Number of moles of H2 = number of moles of Zn
= 3.97 mol (approx)
Step 3: Calculate the volume of hydrogen gas at STP using the molar volume.
The molar volume of a gas at STP is 22.4 L/mol.
Volume of H2 at STP = number of moles of H2 x molar volume
= 3.97 mol x 22.4 L/mol
= 88.928 L (approx)
Therefore, approximately 88.9 liters of hydrogen gas is produced at STP when 260 g of zinc reacts with excess hydrochloric acid.
To find the volume of hydrogen gas produced at standard temperature and pressure (STP) when 260g of zinc reacts with excess HCl acid, we need to follow these steps:
1. Write the balanced chemical equation for the reaction.
Zn + 2HCl → ZnCl2 + H2
2. Calculate the number of moles of zinc (Zn) using its molar mass.
Molar mass of Zn = 65.38 g/mol
Moles of Zn = Mass of Zn / Molar mass of Zn
= 260g / 65.38 g/mol
≈ 3.975 mol (rounded to three decimal places)
3. According to the balanced chemical equation, we know that 1 mole of zinc reacts to produce 1 mole of hydrogen gas (H2).
4. Convert the number of moles of hydrogen gas to the volume of gas using the ideal gas law equation:
PV = nRT
Where P = pressure (at STP, it is 1 atmosphere)
V = volume (what we want to find)
n = number of moles of gas
R = ideal gas constant (0.0821 L.atm/mol.K)
T = temperature in Kelvin (at STP, it is 273.15 K)
Rearranging the equation, we get:
V = (nRT) / P
Plugging in the values, we have:
V = (3.975 mol * 0.0821 L.atm/mol.K * 273.15 K) / 1 atm
≈ 89.4 L (rounded to one decimal place)
Therefore, approximately 89.4 liters of hydrogen gas would be produced at STP when 260g of zinc reacts with excess HCl acid.