What volume of hydrogen is produced at STP when 2•60g of zinc reacts with excess HCl according to the equation below
Zn+2HCL>ZnCl+H2
Zn=65,1 mole of a gas occupies 22•4 dm3 at STP.
To solve this problem, we need to use stoichiometry to find the number of moles of hydrogen gas produced, and then convert that to volume using the given information.
First, let's calculate the number of moles of zinc (Zn) used in the reaction. The molar mass of zinc (Zn) is 65.1 g/mol.
Number of moles of Zn = mass of Zn / molar mass of Zn
Number of moles of Zn = (2 * 60 g) / 65.1 g/mol
Number of moles of Zn = 1.847 moles
According to the balanced equation, 1 mole of zinc reacts to produce 1 mole of hydrogen gas (H2). Therefore, the number of moles of hydrogen gas produced is also 1.847 moles.
Now let's convert the number of moles of hydrogen gas to volume at STP. 1 mole of any gas occupies 22.4 dm3 at STP.
Volume of hydrogen gas = number of moles of H2 * 22.4 dm3/mol
Volume of hydrogen gas = 1.847 moles * 22.4 dm3/mol
Volume of hydrogen gas = 41.2976 dm3
Therefore, the volume of hydrogen gas produced at STP when 2 * 60 g of zinc reacts with excess HCl is 41.3 dm3.
To find the volume of hydrogen gas produced at STP, we can follow the given equation and use stoichiometry calculations.
Step 1: Calculate the number of moles of zinc (Zn) used.
Given mass of zinc (Zn) = 2.60 g
Molar mass of zinc (Zn) = 65.1 g/mol
Number of moles = Mass / Molar mass
Number of moles of Zn = 2.60 g / 65.1 g/mol
Step 2: Determine the limiting reactant.
Since HCl is in excess, we assume that zinc (Zn) is the limiting reactant.
Step 3: Use stoichiometry to find the number of moles of hydrogen gas (H2) produced.
From the balanced equation:
1 mole of zinc (Zn) produces 1 mole of hydrogen gas (H2)
Therefore, the number of moles of H2 = Number of moles of Zn.
Step 4: Convert moles of hydrogen gas (H2) to volume at STP.
At STP, 1 mole of any gas occupies 22.4 dm^3 (or L).
Therefore, the volume of H2 (in dm^3 or L) = Number of moles of H2 * 22.4 dm^3/mol
Now, let's calculate the volume of hydrogen gas produced at STP:
Step 1: Calculate the number of moles of Zn:
Number of moles of Zn = 2.60 g / 65.1 g/mol = 0.0399 mol
Step 2: Since Zn is the limiting reactant, the number of moles of H2 produced is also 0.0399 mol.
Step 3: Convert moles of H2 to volume at STP:
Volume of H2 = 0.0399 mol * 22.4 dm^3/mol
Therefore, the volume of hydrogen gas produced at STP is approximately 0.894 dm^3 or 0.894 L.
To determine the volume of hydrogen gas produced at STP (Standard Temperature and Pressure), we need to follow these steps:
1. Calculate the moles of zinc (Zn) using the given mass and molar mass:
Moles of Zn = Mass of Zn / Molar mass of Zn
Moles of Zn = 2.60 g / 65.1 g/mol
2. Since the equation tells us that 1 mole of Zn reacts to produce 1 mole of H2, the number of moles of hydrogen gas (H2) produced will be the same as the moles of zinc.
3. Convert the moles of H2 gas to volume using the given information:
Volume of 1 mole of gas at STP = 22.4 dm³
Volume of H2 gas = Moles of H2 gas x Volume of 1 mole of gas at STP
Volume of H2 gas = Moles of H2 gas x 22.4 dm³
Now let's calculate the volume of hydrogen gas produced:
Moles of Zn = 2.60 g / 65.1 g/mol
Moles of Zn = 0.03998 mol (rounded to 4 decimal places)
Since the moles of H2 gas produced will be the same as the moles of Zn, the volume of H2 gas is:
Volume of H2 gas = 0.03998 mol x 22.4 dm³/mol
Volume of H2 gas = 0.895 dm³
Therefore, approximately 0.895 dm³ (or 895 mL) of hydrogen gas is produced at STP when 2.60 g of zinc reacts with excess HCl.