what volume of 0.4M sodium chloride will contain 0.585g of NaCl
molar mass NaaCl = 58.5
mols NaCl in 0.585 g is g/molar mass = 0.585/58.5 = 0.01
Then M = mols/L. YOu know mols and you know M, solve for L.
Convert to mL if required.
To calculate the volume of a solution containing a known mass of solute, you need to use the equation:
Volume (in liters) = Mass (in grams) / Concentration (in moles per liter)
First, you need to convert the mass of NaCl from grams to moles. The molar mass of NaCl is approximately 58.44 g/mol. Therefore:
0.585g NaCl * (1 mol NaCl / 58.44 g NaCl) = 0.010 mol NaCl
Next, we can use the concentration of sodium chloride (0.4M) to determine the volume of the solution containing 0.010 moles of NaCl:
Volume (in liters) = 0.010 mol NaCl / 0.4 mol/L = 0.025 L or 25 mL
Therefore, 0.585g of NaCl will require a volume of approximately 25 mL of a 0.4M sodium chloride solution.