What volume of 0.4m sodium chloride will certain 0.58g of Nacl.
To solve this problem, we need to use the formula:
moles = mass / molar mass
First, we need to calculate the number of moles of NaCl:
moles = 0.58g / 58.44 g/mol = 0.01 moles
Next, we can use the formula for molarity:
Molarity = moles / volume (in liters)
We know the molarity (0.4 M) and the number of moles (0.01 moles), so we can rearrange the formula to solve for volume:
Volume = moles / molarity
Volume = 0.01 moles / 0.4 M = 0.025 L or 25 mL
Therefore, the volume of 0.4 M sodium chloride needed to obtain 0.58 g of NaCl is 25 mL.
To determine the volume of a solution, we need to know its concentration. In this case, you've mentioned a concentration of 0.4 molar (0.4 M) sodium chloride.
To find the volume, we can use the formula:
Volume (in liters) = Mass (in grams) / Concentration (in moles per liter)
First, we need to convert the mass of sodium chloride (NaCl) to moles. The molar mass of NaCl is 58.44 g/mol.
Number of moles = Mass / Molar Mass
= 0.58 g / 58.44 g/mol
≈ 0.0099274 moles
Now, let's calculate the volume:
Volume (in liters) = 0.0099274 moles / 0.4 moles/L
= 0.0248185 L
Therefore, approximately 0.0248 liters (or 24.8 mL) of the 0.4 M sodium chloride solution will contain the given 0.58 grams of NaCl.