If we add the ages of three brothers bharat, mahesh, and ramesh then it becomes 60 years today. If 6 years ago ramesh was of half the age of mahesh
B+M+R =60 (short names of the 3 boys)
Write down the equation as per given question for 6 years ago
6years ago, the equation will be after solving
R=(6+M)/2
B=3*((6+M)/2 )-12
So, 6 years ago
B+M+R=60-6-6-6 (SUBSTRACT 6 3times)
B+M+R=42
REPLACE THE VALUES OF B, R AND FIND MAHESH AGE
MAHESH AGE =14 answer
If u can't find the solution then u play ludu.
Let's solve this step-by-step:
Step 1: Assign variables to the ages of the three brothers.
Let's say Bharat's age is B, Mahesh's age is M, and Ramesh's age is R.
Step 2: Translate the given information into equations.
The sum of their ages today is 60: B + M + R = 60.
Ramesh was half the age of Mahesh six years ago: R - 6 = (1/2)(M - 6).
Step 3: Simplify the equations.
R - 6 = (1/2)(M - 6) can be rewritten as 2R - 12 = M - 6.
Step 4: Rearrange one of the equations to isolate a variable.
From the equation B + M + R = 60, we can rearrange it to B = 60 - M - R.
Step 5: Substitute the rearranged equation into the other equation.
Substituting B = 60 - M - R into 2R - 12 = M - 6, we get 2R - 12 = M - 6 - (60 - M - R).
Step 6: Simplify and solve for one variable.
Simplifying the equation further, we get 2R - 12 = -66 + 2M + 2R.
Step 7: Combine like terms.
Rearranging the equation, we have 2M + 12 = 52.
Step 8: Solve for M.
Subtracting 12 from both sides, we have 2M = 40.
Dividing by 2, we get M = 20.
Step 9: Substitute the value of M into one of the equations.
Using the equation B + M + R = 60, we have B + 20 + R = 60.
Step 10: Solve for B.
Subtracting 20 from both sides, we get B + R = 40.
Step 11: Substitute the values of M and B into the original equation.
Using the equation R - 6 = (1/2)(M - 6), we can substitute M = 20 and B = 40.
Step 12: Solve for R.
Substituting the values, we have R - 6 = (1/2)(20 - 6).
Simplifying, we get R - 6 = (1/2)(14).
Multiplying both sides by 2, we have 2R - 12 = 14.
Adding 12 to both sides, we get 2R = 26.
Dividing by 2, we get R = 13.
So, Bharat is 40 years old, Mahesh is 20 years old, and Ramesh is 13 years old.
To solve this problem, we can use a system of equations.
Let's assign variables to the ages of the three brothers:
- Let's say Bharat's age is B years.
- Mahesh's age is M years.
- Ramesh's age is R years.
According to the given information, the sum of their ages is 60 years today: B + M + R = 60.
We are also given that 6 years ago, Ramesh was half the age of Mahesh: R - 6 = 0.5(M - 6).
We can simplify this equation by multiplying everything by 2 to remove the fraction:
2R - 12 = M - 6.
Now, we have a system of two equations:
1. B + M + R = 60.
2. 2R - 12 = M - 6.
We can solve this system of equations to find the ages of the brothers.
First, let's solve Equation 2 for M:
M = 2R - 6 + 12.
M = 2R + 6.
Substitute this expression for M in Equation 1:
B + (2R + 6) + R = 60.
Combine like terms:
B + 3R + 6 = 60.
Subtract 6 from both sides:
B + 3R = 54.
Now we have a system of two equations:
1. B + 3R = 54.
2. 2R - 12 = 2R + 6.
From Equation 2, we can see that 2R cancels on both sides, leaving us with -12 = 6. However, this is not possible and indicates that there is no consistent solution for this problem. It is likely there was an error in the information given or during the problem setup.
Therefore, we cannot determine the ages of the three brothers with the given information.